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  • What is the product of the following reaction? 1)CH_3 OH - Socratic
    These are ostensibly acid-base reactions For ammonium we could write NH_4^+ +HO^(-) rarr NH_3(aq) + H_2O(l) For methanol, the acid base reaction would proceed
  • Can you give the IUPAC name for the following (CH_3)_3C-OH . . . - Socratic
    So this is a propanol derivative: "2-methylpropan-2-ol" For "isopropyl alcohol", H_3C-CH (OH)CH_3, the longest chain is again three carbons long, and C2 is substituted by -OH, so "propan-2-ol" I think this is right, and I haven't broken any arcane rule Both names seem to be unambiguous
  • Question #6f366 - Socratic
    Here's what I get > The reaction is a simple proton transfer from the acid to the amine to form an ammonium salt The equation for the salt formation is underbrace
  • Question #54b11 - Socratic
    The balanced equation is "CH"_3"CH"_2"COO"^"-" + "3S" + 4"OH"^"-" → "CH"_3"COO"^"-" + "HCO"_3^"-" + "3HS"^"-" + "H"_2"O" > The reaction is carried out at pH 8, so we must balance in basic solution
  • Question #851e9 + Example - Socratic
    The equation for this is: H^+ (aq)+OH^ (-) (aq)rightleftharpoonsH_2O (l) A common example of a neutralization reaction would be adding hydrochloric acid to aqueous sodium hydroxide
  • Question #bb4d7 - Socratic
    Since there are both H^+ and OH^- ions in water, bicarbonate ions get hydrated really quickly to form carbonic acid, and the equation is HCO_3^ (-)+H^+rightleftharpoonsH_2CO_3 Know that, carbonic acid is a weak acid This leaves OH^- in excess, and they bond with Na^+ ions to form sodium hydroxide (NaOH), a strong base
  • Answers created by Paul - Socratic
    Q A and Videos that make learning easy Math, History, Chemistry, Algebra, Calculus, Biology and more
  • Question #53967 - Socratic
    a HI (aq) rarr H^ (+) + I^- b HNO_3 (aq) rarr H^ (+) + NO_3^- c Ba (OH)_2 (aq) rarr Ba^ (2+) + 2HO^- "Hydrogen iodide" is in fact a very strong acid; as is "nitric acid", HNO_3 (in fact the former is a stronger acid than the latter!)
  • Question #22e51 - Socratic
    Products formed are; Cu (OH)_2 + HCl -> CuCl_2 + H_2O Since CuCl_2 is soluble in water But; Cu (OH)_2 + HCl -> CuCl_2 + H_2O " [Not Balanced]" Balancing the equation
  • Question #627ef - Socratic
    functional groups like -OH, -CHO,-CO- are present in carbohydrates commonly two functional are present in a carbohydrate,-OH and -CHO, or -OH and-CO- Aldose shows different reactions and test like Tollen's silver mirror test, felling's test different types of reactions are also shown by carbohydrates like Osazone synthesis, length increasing reaction, oxidation reactions These are all due





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